这个问题在这里已经有了答案:关闭11年前。PossibleDuplicate:JavaScriptasynchronousreturnvalue/assignmentwithjQuery我需要一个带有构造函数的图表原型(prototype),所以我这样写:functionChart(file){varchart=undefined$.getJSON(file,function(data){chart={categories:data.keysseries:[{name:'first',data:data.first},{name:'second',data:data.second}]}
我目前有一个运行大约200次的函数。函数如下所示:functionGetB(av,bol){varbxes=[["11","12","13","21","22","23","31","32","33"],["14","15","16","24","25","26","34","35","36"],["17","18","19","27","28","29","37","38","39"],["41","42","43","51","52","53","61","62","63"],["44","45","46","54","55","56","64","65","66"],["47",
我编写了一个简单的代码来捕获字符串中的特定组:/[a-z]+([0-9]+)[a-z]+/gi(nchars,mdigts,kchars).code:varmyString='aaa111bbb222ccc333ddd';varmyRegexp=/[a-z]+([0-9]+)[a-z]+/gi;varmatch=myRegexp.exec(myString);console.log(match)while(match!=null){match=myRegexp.exec(myString);console.log(match)}结果是:["aaa111bbb","111"]["ccc3
我正在处理电话验证,需要使用电话号码自动格式化输入,并且只允许添加数字字符。但是,当我尝试使用keydown和keypress限制输入时,iPhone允许我输入#和*。当我检查keydown值时,它们分别与3和8相同(键码51和56)。这在Android浏览器中完美运行,但在iPhone中失败。任何人都遇到过类似的问题。$(formSelector+'input[name^="phone"]').on('keydownkeypress',function(e){//Allow:backspace,delete,tab,escape,andenterif(e.keyCode==46||e